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A machine bought for ₹6,25,000 loses 20% of its value every year. Its value at the end of 3 years is:

Competition practiceAlgebra
  • A₹4,00,000
  • B₹2,50,000
  • C₹3,75,000
  • D₹3,20,000

Step-by-Step Solution

Each year the value is multiplied by 0.8, so the values form a geometric progression: 6,25,000 → 5,00,000 → 4,00,000 → 3,20,000. In symbols = ₹3,20,000. (Subtracting 20% of the original three times would wrongly give ₹2,50,000.)
Answer: D) ₹3,20,000

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