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A positive number satisfies /(3 + 1/(3 + …)), the pattern continuing without end. Then equals:

Competition practiceAlgebra
  • A(3 + √13)/2
  • B(3 + √5)/2
  • C(3 − √13)/2
  • D(√13 − 3)/2

Step-by-Step Solution

The whole tail after the first 3 repeats the original expression, so . Multiplying by gives , so = (3 ± √13)/2, and only the positive sign can equal an expression bigger than 3. (The negative root (3 − √13)/2 ≈ −0.30 is rejected; (√13 − 3)/2 solves instead; (3 + √5)/2 belongs to .) Numerically ≈ 3.3028, and 3 + 1/3.3028 ≈ 3.3028.
Answer: A) (3 + √13)/2

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