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Find the sum of the first 15 terms of the arithmetic progression 2, 5, 8, 11, ...

Competition practiceAlgebra

A345
B335
C350
D320

Step-by-Step Solution

Here

a = 2, d = 3, n = 15

. Sum =

(n /2) [2 a + (n - 1) d] = (15/2) [4 + 14 \times 3] = (15/2) (46) = 345

.

Answer: A) 345

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