For a ≠ 0 and a ≠ ±b, the value of (a² − b²)/(a² + ab) ÷ (a − b)/a is:

Question

Accepted Answer

1. First (a² − b²)/(a² + ab) = (a − b)(a + b)/(a(a + b)) = (a − b)/a. Dividing by (a − b)/a means multiplying by a/(a − b), so the value is 1. (With a = 3 and b = 2: (5/15) ÷ (1/3) = 1.)

For a ≠ 0 and a ≠ ± $b$ , the value of $(a^{2} - b^{2}) / (a^{2} + ab) \div (a - b) / a$ is:

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For a ≠ 0 and a ≠ ±b, the value of (a2−b2)/(a2+ab)÷(a−b)/a is:

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Algebra practice

For a ≠ 0 and a ≠ ± $b$ , the value of $(a^{2} - b^{2}) / (a^{2} + ab) \div (a - b) / a$ is: