If 47x + 31y = 63 and 31x + 47y = 15, then x − y equals:

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3. Adding the equations gives 78x + 78y = 78, so x + y = 1. Subtracting them gives 16x − 16y = 48, so x − y = 3. (Then x = 2 and y = −1, and 47(2) + 31(−1) = 63.)

If $47 x + 31 y = 63$ and $31 x + 47 y = 15$ , then $x - y$ equals:

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If 47x+31y=63 and 31x+47y=15, then x−y equals:

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Algebra practice

If $47 x + 31 y = 63$ and $31 x + 47 y = 15$ , then $x - y$ equals: