If a + b + c = 12 and ab + bc + ca = 47, then a² + b² + c² equals:

Question

Accepted Answer

50. (a + b + c)² = a² + b² + c² + 2(ab + bc + ca), so 144 = a² + b² + c² + 94, giving a² + b² + c² = 50. (For example a, b, c = 3, 4, 5 fits both conditions.)

If $a + b + c = 12$ and $ab + b c + c a = 47$ , then $a^{2} + b^{2} + c^{2}$ equals:

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If a+b+c=12 and ab+bc+ca=47, then a2+b2+c2 equals:

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Algebra practice

If $a + b + c = 12$ and $ab + b c + c a = 47$ , then $a^{2} + b^{2} + c^{2}$ equals: