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In an arithmetic progression the 4th term is 11 and the 12th term is 35. Its 20th term is:

Competition practiceAlgebra
  • A47
  • B59
  • C62
  • D56

Step-by-Step Solution

a + 3d = 11 and a + 11d = 35, so 8d = 24, d = 3 and a = 2. Then a₂₀ = a + 19d = 2 + 57 = 59. (47 is the 16th term — the result of adding only 4d to the 12th term; 62 comes from using a + 20d instead of a + 19d; 56 is the 19th term.)
Answer: B) 59

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