The complete factorisation of x³ − 6x² + 11x − 6 is:

Question

Accepted Answer

(x − 1)(x − 2)(x − 3). p(1) = 1 − 6 + 11 − 6 = 0, so (x − 1) is a factor. Dividing gives x² − 5x + 6 = (x − 2)(x − 3). Hence the factorisation is (x − 1)(x − 2)(x − 3).

The complete factorisation of $x^{3} - 6 x^{2} + 11 x - 6$ is:

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More Algebra practice

The complete factorisation of x3−6x2+11x−6 is:

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Algebra practice

The complete factorisation of $x^{3} - 6 x^{2} + 11 x - 6$ is: