The product of all the real roots of x⁴ − 13x² + 36 = 0 is:

Question

Accepted Answer

36. Put y = x². Then y² − 13y + 36 = 0, i.e. (y − 4)(y − 9) = 0, so x² = 4 or x² = 9. The four real roots are 2, −2, 3 and −3, whose product is (2)(−2)(3)(−3) = 36.

The product of all the real roots of $x^{4} - 13 x^{2} + 36 = 0$ is:

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More Algebra practice

The product of all the real roots of x4−13x2+36=0 is:

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Algebra practice

The product of all the real roots of $x^{4} - 13 x^{2} + 36 = 0$ is: