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The sum of the first 20 terms of the arithmetic progression 2, 5, 8, 11, ... is:

Competition practiceAlgebra

A610
B590
C620
D600

Step-by-Step Solution

With

a = 2, d = 3, n = 20

: Sₙ =

(n /2) [2 a + (n - 1) d] = 10 [4 + 57] = 10 \times 61 = 610

.

Answer: A) 610

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