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The sum of the first six terms of the geometric progression 3, 6, 12, ... is:

Competition practiceAlgebra

A96
B192
C189
D381

Step-by-Step Solution

Here

a = 3

and

r = 2

, so S₆ =

a (r^{6} - 1) / (r - 1) = 3 (64 - 1) /1 = 189

. Directly: 3 + 6 + 12 + 24 + 48 + 96 = 189.

Answer: C) 189

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