Two zeros of the cubic polynomial x³ − 4x² + x + 6 are 2 and 3. The third zero is:

Question

Accepted Answer

−1. The sum of the zeros is −(−4)/1 = 4, so the third zero is 4 − (2 + 3) = −1. It checks against the product too: the product of the zeros is −6/1 = −6 and 2 × 3 × (−1) = −6. Substituting, p(−1) = −1 − 4 − 1 + 6 = 0.

Two zeros of the cubic polynomial $x^{3} - 4 x^{2} + x + 6$ are 2 and 3. The third zero is:

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Two zeros of the cubic polynomial x3−4x2+x+6 are 2 and 3. The third zero is:

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Algebra practice

Two zeros of the cubic polynomial $x^{3} - 4 x^{2} + x + 6$ are 2 and 3. The third zero is: