- AIt is positive for every real value of
- BIt is negative for every real value of
- CIt is positive only when
- DIt is zero for exactly one real value of
Step-by-Step Solution
, which is at least 3 for every real . Its discriminant 16 − 28 = −12 is negative, so it never reaches zero and stays positive throughout.
Answer: A) It is positive for every real value of