A chord of a circle of radius 12 cm subtends an angle of 60° at the centre. Find the area (in cm²) of the corresponding minor segment. Take π = 3.14 and √3 = 1.73.

Question

Accepted Answer

13.08. Sector area = (60/360) × 3.14 × 144 = (1/6) × 452.16 = 75.36 cm². The two radii and the chord form an equilateral triangle of side 12 cm, whose area = (1.73/4) × 144 = 62.28 cm². Segment = 75.36 − 62.28 = 13.08 cm².

A chord of a circle of radius 12 cm subtends an angle of 60° at the centre. Find the area (in $cm^{2}$ ) of the corresponding minor segment. Take π = 3.14 and √3 = 1.73.

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More Areas & Volumes practice

A chord of a circle of radius 12 cm subtends an angle of 60° at the centre. Find the area (in cm2) of the corresponding minor segment. Take π = 3.14 and √3 = 1.73.

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Areas & Volumes practice

A chord of a circle of radius 12 cm subtends an angle of 60° at the centre. Find the area (in $cm^{2}$ ) of the corresponding minor segment. Take π = 3.14 and √3 = 1.73.