A circular running track has an inner circumference of 352 m, and the track itself is 7 m wide all the way round. Find the area of the track in m². Take π = 22/7.

Question

Accepted Answer

2618. 2 × (22/7) × r = 352 gives r = 56 m, so the outer radius R = 56 + 7 = 63 m. Track area = π(R² − r²) = (22/7)(3969 − 3136) = (22/7) × 833 = 22 × 119 = 2618 m².

A circular running track has an inner circumference of 352 $m$ , and the track itself is 7 $m$ wide all the way round. Find the area of the track in $m^{2}$ . Take π = 22/7.

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Areas & Volumes practice

A circular running track has an inner circumference of 352 m, and the track itself is 7 m wide all the way round. Find the area of the track in m2. Take π = 22/7.

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Areas & Volumes practice

A circular running track has an inner circumference of 352 $m$ , and the track itself is 7 $m$ wide all the way round. Find the area of the track in $m^{2}$ . Take π = 22/7.