A circus tent has a cylindrical base of diameter 42 m and height 5 m, surmounted by a cone of slant height 25 m. Canvas costs ₹60 per m² and no canvas is laid on the ground. Find the total cost in rupees. Take π = 22/7.

Question

Accepted Answer

138600. Radius = 21 m. Cylinder curved surface = 2 × (22/7) × 21 × 5 = 660 m². Cone curved surface = (22/7) × 21 × 25 = 1650 m². Canvas = 660 + 1650 = 2310 m², so the cost = 2310 × 60 = ₹138600.

A circus tent has a cylindrical base of diameter 42 $m$ and height 5 $m$ , surmounted by a cone of slant height 25 $m$ . Canvas costs ₹60 per $m^{2}$ and no canvas is laid on the ground. Find the total cost in rupees. Take π = 22/7.

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A circus tent has a cylindrical base of diameter 42 m and height 5 m, surmounted by a cone of slant height 25 m. Canvas costs ₹60 per m2 and no canvas is laid on the ground. Find the total cost in rupees. Take π = 22/7.

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A circus tent has a cylindrical base of diameter 42 $m$ and height 5 $m$ , surmounted by a cone of slant height 25 $m$ . Canvas costs ₹60 per $m^{2}$ and no canvas is laid on the ground. Find the total cost in rupees. Take π = 22/7.