A room is 8 m long, 6 m wide and 4 m high. Whitewashing its four walls and the ceiling costs ₹12 per m². Find the total cost in rupees.

Question

Accepted Answer

1920. Area of the four walls = 2(l + b)h = 2(8 + 6) × 4 = 112 m². Ceiling = 8 × 6 = 48 m². Total = 160 m², so the cost = 160 × 12 = ₹1920.

A room is 8 $m$ long, 6 $m$ wide and 4 $m$ high. Whitewashing its four walls and the ceiling costs ₹12 per $m^{2}$ . Find the total cost in rupees.