A triangle has a base 18 cm long and the height drawn to that base is 9 cm. A square is drawn inside the triangle with one whole side on the base and its two upper corners on the other two sides. Find the area of the square in cm².

Question

Accepted Answer

36. Let the square have side s. At height s above the base the triangle has narrowed to a width of 18(1 − s/9), and that width must equal s. So 18 − 2s = s, giving 3s = 18 and s = 6 cm. Area = 6² = 36 cm².

A triangle has a base 18 cm long and the height drawn to that base is 9 cm. A square is drawn inside the triangle with one whole side on the base and its two upper corners on the other two sides. Find the area of the square in $cm^{2}$ .

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More Areas & Volumes practice

A triangle has a base 18 cm long and the height drawn to that base is 9 cm. A square is drawn inside the triangle with one whole side on the base and its two upper corners on the other two sides. Find the area of the square in cm2.

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Areas & Volumes practice

A triangle has a base 18 cm long and the height drawn to that base is 9 cm. A square is drawn inside the triangle with one whole side on the base and its two upper corners on the other two sides. Find the area of the square in $cm^{2}$ .