A wiper arm turns about a fixed pivot through an angle of 90°. The rubber blade does not reach the pivot: it covers only the stretch of the arm lying between 10 cm and 24 cm from the pivot. Find the area wiped clean in cm². Take π = 22/7.

Question

Accepted Answer

374. The clean region is the part of a ring between radii 10 cm and 24 cm cut off by a 90° turn. Area = (90/360) × π(24² − 10²) = ¼ × (22/7) × (576 − 100) = ¼ × (22/7) × 476 = ¼ × 1496 = 374 cm².

A wiper arm turns about a fixed pivot through an angle of 90°. The rubber blade does not reach the pivot: it covers only the stretch of the arm lying between 10 cm and 24 cm from the pivot. Find the area wiped clean in $cm^{2}$ . Take π = 22/7.

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More Areas & Volumes practice

A wiper arm turns about a fixed pivot through an angle of 90°. The rubber blade does not reach the pivot: it covers only the stretch of the arm lying between 10 cm and 24 cm from the pivot. Find the area wiped clean in cm2. Take π = 22/7.

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Areas & Volumes practice

A wiper arm turns about a fixed pivot through an angle of 90°. The rubber blade does not reach the pivot: it covers only the stretch of the arm lying between 10 cm and 24 cm from the pivot. Find the area wiped clean in $cm^{2}$ . Take π = 22/7.