An equilateral triangle has side 14 cm. At each of its three corners a sector of radius 7 cm is cut away, the two straight edges of every sector lying along the two sides that meet at that corner. Find the area left, in cm². Take π = 22/7 and √3 = 1.73.

Question

Accepted Answer

7.77. Triangle area = (√3/4) × 14² = 1.73 × 49 = 84.77 cm². The three corner angles add up to 180°, so the three sectors together make exactly half a circle of radius 7 cm: ½ × (22/7) × 49 = 77 cm². (The radius is half the side, so neighbouring sectors just meet and never overlap.) Area left = 84.77 − 77 = 7.77 cm².

An equilateral triangle has side 14 cm. At each of its three corners a sector of radius 7 cm is cut away, the two straight edges of every sector lying along the two sides that meet at that corner. Find the area left, in $cm^{2}$ . Take π = 22/7 and √3 = 1.73.

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More Areas & Volumes practice

An equilateral triangle has side 14 cm. At each of its three corners a sector of radius 7 cm is cut away, the two straight edges of every sector lying along the two sides that meet at that corner. Find the area left, in cm2. Take π = 22/7 and √3 = 1.73.

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Areas & Volumes practice

An equilateral triangle has side 14 cm. At each of its three corners a sector of radius 7 cm is cut away, the two straight edges of every sector lying along the two sides that meet at that corner. Find the area left, in $cm^{2}$ . Take π = 22/7 and √3 = 1.73.