In trapezium ABCD the side AB is parallel to DC, with AB = 26 cm and DC = 16 cm. The side AD stands perpendicular to both parallel sides, and the fourth side BC is 26 cm. Find the area of ABCD in cm².

Question

Accepted Answer

504. Dropping a perpendicular from C to AB leaves a horizontal piece of 26 − 16 = 10 cm. In that right triangle the hypotenuse is BC = 26 cm, so the height AD = √(26² − 10²) = √576 = 24 cm. Area = ½ × (26 + 16) × 24 = ½ × 42 × 24 = 504 cm².

In trapezium ABCD the side AB is parallel to DC, with AB = 26 cm and DC = 16 cm. The side AD stands perpendicular to both parallel sides, and the fourth side BC is 26 cm. Find the area of ABCD in $cm^{2}$ .

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In trapezium ABCD the side AB is parallel to DC, with AB = 26 cm and DC = 16 cm. The side AD stands perpendicular to both parallel sides, and the fourth side BC is 26 cm. Find the area of ABCD in cm2.

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Areas & Volumes practice

In trapezium ABCD the side AB is parallel to DC, with AB = 26 cm and DC = 16 cm. The side AD stands perpendicular to both parallel sides, and the fourth side BC is 26 cm. Find the area of ABCD in $cm^{2}$ .