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The areas of three adjacent faces of a cuboid are $15 cm^{2}, 20 cm^{2}$ and $12 cm^{2}$ . Find its volume in $cm^{3}$ .

Competition practiceAreas & Volumes

A47
B120
C60
D30

Step-by-Step Solution

If the faces are lb,

bh

and

h l

, their product is

(l bh)^{2}

. So

V^{2} = 15 \times 20 \times 12 = 3600

and

V = 60 cm^{3}

. (The cuboid is 5 by 3 by 4.)

Answer: C) 60

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