Two sides of a triangle measure 8 cm and 10 cm, and the angle between them is 30°. Find the area of the triangle in ${\text{cm}}^2$.

Area = ½ × ab × sin $C$ = ½ × $8\times 10$ × sin 30° = ½ × 80 × ½ = $20{\text{cm}}^2$. (Dropping the ½ from the formula gives $40{\text{cm}}^2$; reading the angle as 60°, where sin 60° = 0.866, gives $34.64{\text{cm}}^2$; and $80{\text{cm}}^2$ is just the product of the two sides.)