- A2/5
- B9/25
- C1/2
- D1/3
Step-by-Step Solution
P(first red) = 6/10 and then P(second red) = 5/9. Multiplying gives (6/10) × (5/9) = 30/90 = 1/3.
Answer: D) 1/3
A bag contains 6 red and 4 black balls. Two balls are drawn at random one after the other without replacement. What is the probability that both are red?
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