- A5–10
- B10–15
- C15–20
- D20–25
Step-by-Step Solution
Difference the consecutive entries to recover the class frequencies 6, 12, 18, 14, 10, which total 60. The ordinary 'less than' cumulative counts are then 6, 18, 36, 50, 60, and n/2 = 30 is first reached at 36, which belongs to the third class. So the median lies in 10–15.
Answer: B) 10–15