A player scores a goal in a match with probability 1/4, independently of every other match. He plays 3 matches. What is the probability that he scores in at least one of them?

Question

Accepted Answer

37/64. P(no goal in a match) = 3/4, so P(no goal in all three) = (3/4)³ = 27/64. Hence P(at least one goal) = 1 − 27/64 = 37/64.

A player scores a goal in a match with probability 1/4, independently of every other match. He plays 3 matches. What is the probability that he scores in at least one of them?

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