Practice30Create account

In a test the highest mark is 72 and the lowest is 42. Every mark is first increased by 8 and then halved. What is the range of the new marks?

Competition practiceData & Probability
  • A38
  • B30
  • C19
  • D15

Step-by-Step Solution

The original range is 72 − 42 = 30. Adding 8 shifts the highest and the lowest by the same amount, so the gap between them is untouched; halving every mark then halves that gap. The new range is 30 ÷ 2 = 15, and indeed the two extreme marks become (72 + 8)/2 = 40 and (42 + 8)/2 = 25. Answering 30 forgets the halving; 38 = 30 + 8 treats a shift as though it widened the spread; and 19 = (30 + 8)/2 makes the same mistake and then halves it.
Answer: D) 15

Master this topic in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All Data & Probability practice questions

More Data & Probability practice

A bag holds red and blue marbles in the ratio 3 : 5. Four more red marbles are dropped…A single bar 30 cm long represents all 60 students of a class and is divided in…The five numbers 8, 12, x, 20, 26 are written in ascending order, and the mean of the…All four aces and all twelve face cards are taken out of a standard pack of 52 playing…The mean of 20 numbers is 45. One of the numbers is increased by 60 and nothing else…