- AThe mean rises by 8/3 and the median rises by 2
- BThe mean rises by 16 and the median rises by 2
- CThe mean rises by 8/3 and the median is unchanged
- DBoth the mean and the median rise by 8/3
Step-by-Step Solution
Before the correction the six values total 89, so the mean is 89/6, and the median is the average of the middle pair, (14 + 16)/2 = 15. Replacing 14 by 30 adds 16 to the total, giving 105 and a mean of 105/6 = 17.5, a rise of 16/6 = 8/3. In order the corrected data read 9, 11, 16, 18, 21, 30, so the middle pair becomes 16 and 18 and the median rises to 17, a rise of 2. The whole rise of 16 does not go to the mean — it is shared among all six observations — and the median is not always immune to a correction, because here the corrected value crossed the middle of the data.
Answer: A) The mean rises by 8/3 and the median rises by 2