- A25
- B24
- C13
- D36
Step-by-Step Solution
Picture the worst case, in which the twelve months fill as evenly as possible. Two students in every month accounts for 24 students with no month holding three, so 24 is not enough. The next student, the 25th, has to join a month that already holds two, and 25 therefore makes it certain. The answer 24 is the largest number for which it can still fail; 13 answers the easier question about TWO students sharing a month; and is far more than is needed.
Answer: A) 25