- A27
- B33.9
- C25
- D30
Step-by-Step Solution
A cumulative table must be differenced before any averaging: the class frequencies are 4, 8, 18, 14 and 6, which add to 50. With class marks 5, 15, 25, 35 and 45, Σfx = 20 + 120 + 450 + 490 + 270 = 1350, so the mean is 1350 ÷ 50 = 27. Feeding the cumulative entries into the formula as if they were frequencies gives 4740 ÷ 140 ≈ 33.9 — the classic slip, and one that also inflates the head count from 50 to 140. The class mark 25 belongs to the middle row, which is not the same as the average of the data, and 30 is a cumulative entry, that is a count of candidates rather than a score.
Answer: A) 27