- A40°
- B50°
- C80°
- D130°
Step-by-Step Solution
A radius is perpendicular to the tangent at the point of contact, so angle OTP = 90°. The chord TA lies between the radius OT and the ray TP, so angle OTA = 90° − 40° = 50°. As a check, triangle OTA is isosceles with OT = OA, so angle OAT = 50° too and the central angle TOA = 80°, which is exactly twice the tangent–chord angle of 40°, as the alternate-segment theorem requires.
Answer: B) 50°