Practice30Create account

A triangle has sides 6 cm, 8 cm and 10 cm. What is the sum of the squares of the lengths of its three medians?

Competition practiceGeometry
  • A
  • B
  • C
  • D

Step-by-Step Solution

Applying Apollonius' theorem to each median and adding gives the standard result: the sum of the squares of the medians is ¾ of the sum of the squares of the sides. That is ¾ × = ¾ . Checking directly with coordinates (0,0), (8,0), (0,6), the medians are 5, √73 and √52, and 25 + 73 + 52 = 150.
Answer: C)

Master this topic in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All Geometry practice questions

More Geometry practice

In triangle ABC, D is the midpoint of AB. A line through D drawn parallel to BC meets AC…A trapezium is a quadrilateral with at least one pair of parallel sides. In one such…ABCD is a quadrilateral inscribed in a circle, with its vertices in order, and the side…Two circles of radii 10 cm and 17 cm intersect, and their common chord is 16 cm long.…Two circles share the same centre and have radii 25 cm and 24 cm. A chord of the larger…