- A84 cm
- B21 cm
- C42 cm
- D24 cm
Step-by-Step Solution
PQ joins the midpoints of AB and BC, so by the mid-point theorem PQ = ½ × AC = 9 cm, and RS (in triangle ACD) is also 9 cm. QR and SP are the mid-segments of triangles BCD and ABD, so each is ½ × BD = 12 cm. The perimeter is 9 + 12 + 9 + 12 = 42 cm — always the SUM of the two diagonals. Halving only once gives the trap 21 cm, not halving at all gives 84 cm, and 24 cm is merely the longer diagonal.
Answer: C) 42 cm