The areas of two similar triangles are 81 cm² and 49 cm². If a side of the larger triangle is 18 cm, the corresponding side of the smaller triangle is:

Question

Accepted Answer

14 cm. Ratio of areas = ratio of squares of corresponding sides: 81/49 = (18/x)². Taking roots, 9/7 = 18/x ⇒ x = 18 × 7 ÷ 9 = 14 cm.

The areas of two similar triangles are $81 cm^{2}$ and $49 cm^{2}$ . If a side of the larger triangle is 18 cm, the corresponding side of the smaller triangle is:

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The areas of two similar triangles are 81cm2 and 49cm2. If a side of the larger triangle is 18 cm, the corresponding side of the smaller triangle is:

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Geometry practice

The areas of two similar triangles are $81 cm^{2}$ and $49 cm^{2}$ . If a side of the larger triangle is 18 cm, the corresponding side of the smaller triangle is: