- A130
- B100
- C50
- D140
Step-by-Step Solution
In quadrilateral OAPB, angle OAP = angle OBP = 90°. So angle AOB = 360 − 90 − 90 − 50 = 130°.
Answer: A) 130
Two tangents from an external point P touch a circle with centre O at A and B. If angle APB = 50°, find angle AOB. (answer in degrees)
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