What is the area of the triangle whose vertices are (1, 2), (4, 6) and (−3, −2)?

Question

Accepted Answer

2 square units. Area = ½|x₁(y₂ − y₃) + x₂(y₃ − y₁) + x₃(y₁ − y₂)| = ½|1(6 − (−2)) + 4(−2 − 2) + (−3)(2 − 6)| = ½|8 − 16 + 12| = ½ × 4 = 2 square units.

What is the area of the triangle whose vertices are (1, 2), (4, 6) and (−3, −2)?

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