Practice30Create account

The largest number that always divides the product of any four consecutive positive integers is:

Competition practiceNumber & Arithmetic
  • A12
  • B24
  • C48
  • D120

Step-by-Step Solution

Among four consecutive integers there are two even numbers, one of which is a multiple of 4, giving a factor of 8; and at least one is a multiple of 3. So always divides the product. Nothing bigger can be guaranteed, because the very first such product is itself, which is not divisible by 48 or 120.
Answer: B) 24

Master this topic in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All Number & Arithmetic practice questions

More Number & Arithmetic practice

Arrange 5/8, 7/11 and 9/14 in ascending order.The smallest positive integer that leaves remainder 3 on division by 7 and remainder 4…Without multiplying out, the value of 97² − 3² is:A number leaves remainder 3 when divided by 8, and the quotient so obtained leaves…The greatest number that divides 43, 91 and 183 leaving the same remainder in each case…