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The numeral 1101101 is written in base two. What is its value in base ten?

Competition practiceNumber & Arithmetic
  • A91
  • B109
  • C107
  • D219

Step-by-Step Solution

The place values from the left are 64, 32, 16, 8, 4, 2, 1. The digits 1, 1, 0, 1, 1, 0, 1 therefore give 64 + 32 + 0 + 8 + 4 + 0 + 1 = 109. Reading the digits from the wrong end (1011011) gives 64 + 16 + 8 + 2 + 1 = 91, which is the most common slip here.
Answer: B) 109

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