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The sum of five consecutive integers is 2025. The largest of the five is:

Competition practiceNumber & Arithmetic
  • A403
  • B405
  • C407
  • D409

Step-by-Step Solution

With five consecutive integers the middle one is the average, so it is 2025 ÷ 5 = 405. The five numbers are 403, 404, 405, 406, 407 and the largest is 407.
Answer: C) 407

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