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When the digits of a two-digit number are reversed, the new number is 27 more than the original. If the sum of the digits is 11, what is the original number?

Competition practiceNumber & Arithmetic
  • A29
  • B38
  • C47
  • D58

Step-by-Step Solution

Let the digits be a (tens) and b (units). Reversed minus original = 9(b − a) = 27, so b − a = 3. With a + b = 11, we get a = 4 and b = 7. The number is 47 (indeed 74 = 47 + 27).
Answer: C) 47

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