For a = 2026, b = 2025 and c = 2024, find a³ + b³ + c³ − 3abc.

18225. It equals (a + b + c) × ½[(a − b)² + (b − c)² + (c − a)²] = 6075 × ½(1 + 1 + 4) = 6075 × 3 = 18225.

For $a = 2026, b = 2025$ and $c = 2024$ , find $a^{3} + b^{3} + c^{3} - 3 ab c$ .

Competition practiceAlgebra

It equals

(a + b + c)

× ½

[(a - b)^{2} + (b - c)^{2} + (c - a)^{2}] = 6075

× ½

(1 + 1 + 4) = 6075 \times 3 = 18225

Answer: A) 18225

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