If x = √3 + √2, find the value of x³ + 1/x³.

18√3. 1/x = √3 - √2, so x + 1/x = 2√3. x^3 + 1/x^3 = (2√3)^3 - 3(2√3) = 24√3 - 6√3 = 18√3.

If $x$ = √3 + √2, find the value of $x^{3} + 1/ x^{3}$ .

Competition practiceAlgebra

\frac{1}{x} = 3 - 2, so x + \frac{1}{x} = 23 . x^{3} + \frac{1}{x ^{3}} = (23)^{3} - 3 (23) = 243 - 63 = 183

Answer: B) 18√3

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