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The sum of a two-digit number and the number formed by reversing its digits is 121. The digits differ by 3 and the tens digit is larger. Find the number.

Competition practiceAlgebra
  • A74
  • B47
  • C83
  • D65

Step-by-Step Solution

11(a + b) = 121 gives a + b = 11; with a − b = 3, a = 7 and b = 4, so the number is 74.
Answer: A) 74

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