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The zeroes of are α, β and γ. Find α² + β² + γ².

Competition practiceAlgebra
  • A14
  • B36
  • C22
  • D6

Step-by-Step Solution

α + β + γ = 6 and αβ + βγ + γα = 11, so α² + β² + γ² = 36 − 22 = 14. (The zeroes are 1, 2, 3.)
Answer: A) 14

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