The average age of the 5 players in a carrom team is 24 years. The eldest is 6 years above the average and the next eldest is 3 years above it, while the other three players are all the same age as one another. How old is each of those three?

The five ages add to $5\times 24=120$ years. The eldest is 30 and the next eldest 27, together 57, so the other three total 120 - 57 = 63 years and each is 63/3 = 21. Quicker: the top two carry a surplus of 6 + 3 = 9 years above the average, and that surplus has to be balanced by the other three, so each sits 9/3 = 3 years below the average, at 24 - 3 = 21. 24 assumes the equal players must sit at the average, which cannot be, since two players are already above it and something must pull back. 15 takes the whole 9-year surplus off the average instead of sharing it among three players. 27 is the second eldest's age.