- A10
- B11
- C9
- D20
Step-by-Step Solution
Let the son be s; then the father is 45 − s. Five years ago: (45 − s) − 5 = 6(s − 5), so 40 − s = 6s − 30, giving 7s = 70, s = 10.
Answer: A) 10
The sum of the present ages of a father and his son is 45 years. Five years ago the father was six times as old as his son. What is the son's present age (in years)?
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