- A6 h 20 min
- B6 h
- C7 h 20 min
- D5 h 40 min
Step-by-Step Solution
X to Y: 60 ÷ 18 = 3 h 20 min. Y to Z (30 km upstream): 30 ÷ 10 = 3 h. Total = 6 h 20 min.
Answer: A) 6 h 20 min
A launch (14 km/h in still water) goes 60 km downstream from X to Y and then comes back upstream to Z, the midpoint of XY. The current is 4 km/h. What is the total time?
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