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A triangle has sides of 9 cm, 10 cm and 17 cm. What is the radius of its incircle?

Competition practiceGeometry

A2 cm
B4 cm
C3 cm
D1.5 cm

Step-by-Step Solution

s = (9 + 10 + 17) /2 = 18

. Area

= 18 \times 9 \times 8 \times 1 = 1296 = 36 cm^{2}

. Inradius

= \frac{Area}{s} = \frac{36}{18} = 2

cm.

Answer: A) 2 cm

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