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ABC is a right triangle with ∠B = 90°, AB = 15 cm and BC = 20 cm. BD is drawn perpendicular to AC. Find BD.

Competition practiceGeometry

A12 cm
B9 cm
C16 cm
D10 cm

Step-by-Step Solution

A C = 1 5^{2} + 2 0^{2} = 25

cm. Twice the area is

A B \times BC = A C \times B D

, so

B D = \frac{15 \times 20}{25} = 12

cm.

Answer: A) 12 cm

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