ABCD is a cyclic quadrilateral whose diagonals meet at E. If AB = BC, ∠BAC = 30° and ∠DBC = 70°, find ∠ACD.

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50°. ∠BDC = ∠BAC = 30° (same segment BC). In triangle BCD, ∠BCD = 180° - 70° - 30° = 80°. Since AB = BC, ∠BCA = ∠BAC = 30°. So ∠ACD = 80° - 30° = 50°.

ABCD is a cyclic quadrilateral whose diagonals meet at E. If AB = BC, ∠BAC = 30° and ∠DBC = 70°, find ∠ACD.

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